Question

factorise



(l+m)²-4lm​

Answer 1

$= ( {l + m})^{2} - 4lm \\ = {l}^{2} + {m}^{2} + 2lm - 4lm \\ = {l}^{2} + {m}^{2} - 2lm \\ = ( {l - m}^{2} )$

Here you go. And please mark me as the brainliest if you feel it's correct

Answer 2

That's the answer ..........