Math, asked by liya59, 1 year ago

factorise: (l+m)^3 + (2m+3n)^3 +(3n+4l)^3 -3(l+m)(2m+3n)(3n+4l)​

Answers

Answered by shiwkishor
6

Step-by-step explanation:

(l+m)³ + (2m+3n)³ +(3n+4l)³ - 3 (l+m)(2m+3n)(3n+4l)

= (5l+3m+6n){(l+m)²+ (2m+3n)²+(3n+4l)² -(l+m)(2m+3n)-(l+m)(3n+4n) -(2m+3n)(3n+4l)}

Answered by rakeshsharmajbp01
3

Answer:

(5l+3m+6n)(13l²+3m²+4ml+9n²+6nl)

Step-by-step explanation:

Use conditional identity (PART - I)

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