Question

factorise l + m square - 4 l m​

Answer 1

Step-by-step explanation:

(l+m)^2 - 4lm

(l+m)^2 - 4lm=> l^2 +m^2 +2lm - 4lm

(l+m)^2 - 4lm=> l^2 +m^2 +2lm - 4lm=> l^2 +m^2 - 2lm

(l+m)^2 - 4lm=> l^2 +m^2 +2lm - 4lm=> l^2 +m^2 - 2lm=> l^2 + m^2 - 2(l)(m)

(l+m)^2 - 4lm=> l^2 +m^2 +2lm - 4lm=> l^2 +m^2 - 2lm=> l^2 + m^2 - 2(l)(m)=> (l-m) ^2

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