Factorise m^2- .01 Pls help I'm stuck
Answers
Answered by
2
Answer:
Rewrite
1as 1^2
.
m
2
−
1
2
Since both terms are perfect squares, factor using the difference of squares formula,
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
where
a
=
m
and
b
=
1
.
(
m
+
1
)
(
m
−
1
)
Answered by
2
Rewrite 11 as 1212.
Rewrite 11 as 1212.m2−12m2-12
Rewrite 11 as 1212.m2−12m2-12Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=ma=m and b=1b=1.
Rewrite 11 as 1212.m2−12m2-12Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b)a2-b2=(a+b)(a-b) where a=ma=m and b=1b=1.(m+1)(m−1)
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