factorise m*2 - 2mn -21
Answers
Answered by
1
Step-by-step explanation:
solve by -b+under root (b^2-4ac)/2ac
Answered by
1
Answer:
Your question is wrong correct is
m^2-4m-21
m^2-7m+3m-21
(m-7) (m+3) ans......
I will also make your given question by using iota complex no class11
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