Question

factorise m^2+m-12 please solve this question. ​

Answer 1

Answer:

(m + 4) (m - 3)

Step-by-step explanation:

The given polynomial is m² + m - 12

It is of the form ax²+ bx + c.

where

a - coefficient of x²

b - coefficient of x

c - constant term

Comparing the given polynomial with this form, we get

• a = 1

• b = 1

• c = -12

Steps to factorize :

⇒ Find the product of quadratic term [ax²] and constant term [c]

m² × (-12)

-12m²

⇒ Now, find the factors of "-12m²"

 (-m) (12m)

 (m) (-12m)

 (2m) (-6m)

 (-2m) (6m)

 (3m) (-4m)

 (-3m) (4m)

⇒ Find the factors when added equals the linear term [bx]

  (-3m) (4m)

4m - 3m = m

⇒ Split m as 4m and -3m

m² + 4m - 3m - 12

⇒ Find the common factor

m(m + 4) - 3(m + 4)

(m + 4) (m - 3)

∴ m² + 4m - 12 = (m + 4) (m - 3)