factorise m^2+m-12 please solve this question.
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Answer:
(m + 4) (m - 3)
Step-by-step explanation:
The given polynomial is m² + m - 12
It is of the form ax²+ bx + c.
where
a - coefficient of x²
b - coefficient of x
c - constant term
Comparing the given polynomial with this form, we get
- a = 1
- b = 1
- c = -12
Steps to factorize :
⇒ Find the product of quadratic term [ax²] and constant term [c]
m² × (-12)
-12m²
⇒ Now, find the factors of "-12m²"
(-m) (12m)
(m) (-12m)
(2m) (-6m)
(-2m) (6m)
(3m) (-4m)
(-3m) (4m)
⇒ Find the factors when added equals the linear term [bx]
(-3m) (4m)
4m - 3m = m
⇒ Split m as 4m and -3m
m² + 4m - 3m - 12
⇒ Find the common factor
m(m + 4) - 3(m + 4)
(m + 4) (m - 3)
∴ m² + 4m - 12 = (m + 4) (m - 3)
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