Question

factorise=m^8-11m^4 n^4-80n^8​

Answer 1

       

$\Rightarrow\ m^8-11m^4n^4-80n^8 \\ \\ \Rightarrow\ m^8-16m^4n^4+5m^4n^4-80n^8 \\ \\ \Rightarrow\ m^4(m^4-16n^4)+5n^4(m^4-16n^4) \\ \\ \Rightarrow\ (m^4+5n^4)(m^4-16n^4) \\ \\ \Rightarrow\ (m^4+5n^4)(m^2+4n^2)(m^2-4n^2) \\ \\ \Rightarrow\ (m^4+5n^4)(m^2+4n^2)(m+2n)(m-2n) \\ \\ \\ \\ \therefore\ m^8-11m^4n^4-80n^8=\bold{(m^4+5n^4)(m^2+4n^2)(m+2n)(m-2n)}$

$Thank\ you......$

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