factorise (m+n)^2-(m-n)^2
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Answered by
13
Answer:
m²+2mn+n²-(m²-2mn+n²)
m²+2mn+n²-m²+2mn-n²
2mn+2mn
4mn
Answered by
4
Given: A polynomial expression (m+n)² - (m-n)²
To find: Factorisation of the expression
Solution: (m+n)² should follow the rules of (a+b)², where
(a+b)² = a² + 2ab + b².
Similarly, (m-n)² should follow the rules of (a-b)², where
(a-b)² = a² - 2ab + b².
Therefore, putting the values
(m+n)² - (m-n)²
= m² + 2mn + n² - (m² - 2mn + n²)
= m² + 2mn + n² - m² + 2mn - n²
= 2mn + 2mn
= 4mn
Answer: (m+n)² - (m-n)² = 4mn
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