Math, asked by nalingadroo31, 11 months ago

factorise m power 4-n power 4​

Answers

Answered by rash4everall
6

Answer:

m^4 -n^4

=(m²)²-(n²)²

=(m²+n²) (m²-n²)

=(m²+n²) (m+n) (m-n)

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Answered by neerajkrpatel999
2

Answer:

{(m)^2 + (n)^2} {(m)+(n) } {m-n}

Step-by-step explanation:

(m)^4 - (n)^4

{(m)^2}^2 - {(n)^2}^2

let (m)^2 = a

(n)^2 = b

using a^2 -b^2 = (a+b)(a-b)

hence

{(m)^2. +(n)^2}{(m)^2-(n)^2 }

again in {(m)^2-(n)^2 }. [use a^2 -b^2 = (a+b)(a-b)]

{(m)^2 + (n)^2} {(m)+(n) } {m-n}

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