Question

Factorise m square- 23m-120

Answer 1

Answer:

Factoring x2-23x+120

The first term is, x2 its coefficient is 1 .

The middle term is, -23x its coefficient is -23 .

The last term, "the constant", is +120

Step-1 : Multiply the coefficient of the first term by the constant 1 • 120 = 120

Step-2 : Find two factors of 120 whose sum equals the coefficient of the middle term, which is -23 .

-120 + -1 = -121

-60 + -2 = -62

-40 + -3 = -43

-30 + -4 = -34

-24 + -5 = -29

-20 + -6 = -26

-15 + -8 = -23 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and -8

x2 - 15x - 8x - 120

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-15)

Add up the last 2 terms, pulling out common factors :

8 • (x-15)

Step-5 : Add up the four terms of step 4 :

(x-8) • (x-15)

Which is the desired factorization

Step-by-step explanation:

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Answer 2

Answer:

M²-23m+120

m²-15m-8m+120

m(m-15)-8(m-15)

(m-8)(m-15)

m=8,15

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