factorise
m²+1/m²-23
Answers
Answered by
0
Answer:
The required solution is \frac{m^{2} +1}{(m-\sqrt{23})(m+\sqrt{23}) }
(m−
23
)(m+
23
)
m
2
+1
Step-by-step explanation:
The Given expression is :
\frac{m^{2} +1}{m^{2}-23 }
m
2
−23
m
2
+1
We can write 23 as (√23)²
=\frac{m^{2} +1}{m^{2}-(\sqrt{23}) ^{2} }=
m
2
−(
23
)
2
m
2
+1
Applying the Difference of Squares that is:
a^{2} -b^{2} =(a-b)(a+b)a
2
−b
2
=(a−b)(a+b)
=\frac{m^{2} +1}{(m-\sqrt{23})(m+\sqrt{23}) }=
(m−
23
)(m+
23
)
m
2
+1
Answered by
0
Answer:
(m)²+(1/m)²
(m+1/m)²-2.m.1/m
(23)²-2
46-2
=44
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