Question

Factorise: m² - 4mn + 4n²​

Answer 1

Step-by-step explanation:

m²-4mn+4n²

= m²-2(m)(2n) + (2n)²

= (m-n)²

= (m-n)(m-n)

Answer 2

ANSWER

$( {m})^{2} - 4 \times m \times 2n+ (2n)^{2}$

$(m - 2n) ^{2}$

$(m - 2n)(m - 2n)$