Question

FACTORISE -
m2 + 8m + 16

plz solve fast ​

Answer 1

This Equation is an Quardic equation :-

⭐A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared.

⭐The standard form is Ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an variable.

⭐It has only 2 roots.

By using Prime factorization,

➡m² + 8m + 16 = 0

➡m² + 4m + 4m + 16 = 0

➡m(m + 4) + 4(m +4) = 0

➡(m+4)(m+4) = 0

➡m=-4,-4

The roots are -4,-4

is the required answer.

Answer 2

$\Large {\mathfrak {Solution :}}$

The first term is, m² its coefficient is 1 .

The middle term is, +8m its coefficient is 8 .

The last term, "the constant", is +16

Step-1 :

Multiply the coefficient of the first term by the constant 1 • 16 = 16

Step-2 :

Find two factors of 16 whose sum equals the coefficient of the middle term, which is 8 .

-16 + -1 = -17

-8 + -2 = -10

-4 + -4 = -8

-2 + -8 = -10

-1 + -16 = -17

1 + 16 = 17

2 + 8 = 10

4 + 4 = 8 (That's it)

Step-3 :

Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 4 and 4

m2 + 4m + 4m + 16

Step-4 :

Add up the first 2 terms, pulling out like factors :

m(m+4)

Add up the last 2 terms, pulling out common factors :

4(m+4)

Step-5 :

Add up the four terms of step 4 :

(m+4)(m+4)

Which is the desired factorization.