factorise m²-9m-36. give me answer fast please
Answers
Answered by
2
Answer:
m²-9m-36
m²-12m+3m-36
m(m-12)+3(m-12)
(m+3)(m-12)
Step-by-step explanation:
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Answered by
27
How to solve your problem
2−9−36
m^{2}-9m-36m2−9m−36
Grouping
1
Use the sum-product pattern
2−9−36
m^{2}{\color{#c92786}{-9m}}-36m2−9m−36
2+3−12−36
m^{2}+{\color{#c92786}{3m}}{\color{#c92786}{-12m}}-36m2+3m−12m−36
2
Common factor from the two pairs
2+3−12−36
m^{2}+3m-12m-36m2+3m−12m−36
(+3)−12(+3)
m(m+3)-12(m+3)m(m+3)−12(m+3)
3
Rewrite in factored form
(+3)−12(+3)
m(m+3)-12(m+3)m(m+3)−12(m+3)
(−12)(+3)
(m-12)(m+3)(m−12)(m+3)
Solution
(−12)(+3)
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