Factorise m² + mn + 9m + 9n
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Answer:
m²+mn+9m+9n
Do the grouping m²+mn+9m+9n
=(m² +mn)+(9m+9n),
and factor out m in the first and 9 in the second group.
m(m+n)+9(m+n)
Factor out common term m+n by using distributive property.
(m+n)(m+9)
Answered by
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m2 + mn + 9m + 9n
m( 2 + n ) + 9(m + n)
(n + 2) ( m+n) ( m + 9)
m( 2 + n ) + 9(m + n)
(n + 2) ( m+n) ( m + 9)
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