Question

Factorise (m⁴-8) using identity​

Answer 1

Answer:

m(m-2)(m^2 + 2 + 4)

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Step-by-step explanation:

m^4-8

m[m^3-2^3]

m[m^3 + 2m^2 + 4m - 2m^2 - 4m - 8]

m[m(m^2 + 2m + 4) - 2(m^2 + 2m + 4)}

m(m-2)(m^2 + 2 + 4)