Question

factorise mn+nx-mz-nz​

Answer 1

mn+nx-mz-nz

taking common

n(m+x)-z(m+n)

(n-z)(m+n)(m+x)

Answer 2

Answer:

Factorization for mn+nx-mz-nz is (x - z) $\times$ (m + n)

Given Data:

mn+nx-mz-nz

To Find:

Factorize the given data?

Step 1:

Split mx + xn - mz - nz   into two 2-term polynomials

+ xn + mx   and     - mz - nz

This partition did not result in a factorization. We'll try another one.

Step 2:

mx + xn and - mz - nz

This partition looks good

Step 3:

Pull out from each binomial separately

mx + xn = x $\times$  (m + n)

- mz - nz  = - z $\times$ (m + n)

Step 4:

Add up to arrive at the desired factorization

(x - z)$\times$(m + n)