Question

factorise mn(u^2+v^2) -uv(m^2+n^2)​

Answer 1

Step-by-step explanation:

$mn ( {u}^{2} + {v}^{2} ) - uv( {m}^{2} + {n}^{2} )$

Distribute mn through the parentheses

= $mn {u}^{2} + mn {v}^{2} - uv \times ( {m}^{2} + {n}^{2} )$

Distribute -uv through the parentheses

= $mn {u}^{2} + mn {v}^{2} - {m}^{2} uv - {n}^{2} uv$

Here is your answer...

Answer 2

Ans n/(m-n)^2

simplify n^2/m ^2-n ^2

factories=(m+n)(m+n)

please see the picture and answer then judge