Question

factorise msquare-mn+4m-4n

Answer 1

See the pic for answer

Answer 2

The factorasation of $m^{2} -mn+4m-4n$ is $(m+4)(m-n).$

Step-by-step explanation:

We have,

$m^{2} -mn+4m-4n$

To find, the factorasation of $m^{2} -mn+4m-4n$=?

∴ $m^{2} -mn+4m-4n$

$=m(m-n)+4(m-n)$

$=(m+4)(m-n)$

The factorasation of $m^{2} -mn+4m-4n$ is $(m+4)(m-n).$

Hence, the factorasation of $m^{2} -mn+4m-4n$ is $(m+4)(m-n).$