Question

factorise:- (n-10)²+(10-n)​

Answer 1

Answer :}

Now,

(n - 10)^2 + (10 - n)

= (n - 10)^2 - (n - 10)

= (n - 10) (n - 10 - 1)

= (n - 10) (n - 11),

which is the required factorization.

Answer 2

n²+100-20n+10-n

n²-21n+110

n²-11n-10n+110

n(n-11)-10(n-11)

(n-10)(n-11)

n-10=0 or n-11=0

n=10 or n=11