Question

Factorise numerators of this and then divide (a) (4x power 3 + x power 2+ x) divide by x (B) (7a+21) (19z+57) divide by 19 (a+3). (C) (x power 2 - y power 2 ) divide by (x+y)

Answer 1

$4 {x}^{3} + {x}^{2} + x \\ = x(4 {x}^{2} + x + 1) \\ now \: \\ \frac{x(4 {x}^{2} + x + 1) }{x} \\ = 4 {x}^{2} + x + 1 \\ (7a + 21)(19z + 57) \\ = 7 \times 19(a + 3)(z + 3) \\ now \\ \frac{ 7 \times 19(a + 3)(z + 3)}{19(a + 3)} \\ = 7(z + 3) \\ \\ {x}^{2} - {y}^{2} \\ = (x - y)(x + y) \\ now \\ \: \frac{(x - y)(x + y)}{x + y} \\ = x - y$
Hope it helps