Question

factorise of 2y²+6y-20​

Answer 1

Answer:

I) 2y²+6y-20

= 2y²+10y-4y-20

= 2y(y+5) - 4(y+5)

= (y+5)(2y-4)

please mark me as the brainliest

Answer 2

Answer:

2y²+6y-20=> y²+3y-10=0

y²+5y-2y-10=0

y(y+5)-2(y+5)=0

y-2=0 and y+5=0

y=2 and y= -5