Question

factorise of 8x³-(2x-y)³​

Answer 1

Step-by-step explanation:

Given :-

8x^3-(2x-y)^3

To find:-

Factorise the expression 8x^3-(2x-y)^3 ?

Solution:-

Given expression is 8x^3-(2x-y)^3

It can be written as

=> (2x)^2-(2x-y)^3

It is in the form of a^3 - b^3

Where a = 2x and b = 2x-y

We know that

a^3 - b^3 = (a-b)(a^2+ab+b^2)

(2x)^2-(2x-y)^3

=> (2x-(2x-y))[(2x)^2+(2x)(2x-y)+(2x-y)^2]

=> (2x-2x+y)(4x^2+4x^2-2xy+4x^2-4xy+y^2)

=> (y)(12x^2-6xy+y^2)

8x^3-(2x-y)^3 = y (12x^2-6xy+y^2)

(or)

8x^3-(2x-y)^3

=> 8x^3-(8x^3-3(2x)^2(y)+3(2x)(y^2)-y^3)

=>8x^3-8x^3+12x^2y-6xy^2+y^3

=> 12x^2y-6xy^2+y^3

=>y(12x^2-6xy+y^2)

Answer:-

The factorization of 8x^3-(2x-y)^3 is

y(12x^2-6xy+y^2)

Used formulae:-

• a^3 - b^3 = (a-b)(a^2+ab+b^2)

• (a-b)^2= a^2-2ab+b^2

Answer 2

Answer:

heya

Step-by-step explanation:

answer in attachment