factorise of
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P(x)= 2x^3−x^2+13x−6
P(-2)=2(-2)^3-(-2)^2-13(-2)-6
=-16-4+26-6
=-26+26
=0
Therefore x+2 is a factor of p(x)
p(x)=(x+2)(2x^2-5x-3)
=(x+2)(2x^2-6x+x-3)
=(x+2)[(2x(x-3)+1(x-3)]
=(x+2)(2x+1)(x-3)
P(-2)=2(-2)^3-(-2)^2-13(-2)-6
=-16-4+26-6
=-26+26
=0
Therefore x+2 is a factor of p(x)
p(x)=(x+2)(2x^2-5x-3)
=(x+2)(2x^2-6x+x-3)
=(x+2)[(2x(x-3)+1(x-3)]
=(x+2)(2x+1)(x-3)
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