Question

factorise of the following polynomials by take out the monomial as the common factor 5/6a^2+2/3abc-1/6abc​

Answer 1

Answer:

Factors of 6a2b2c=2×3×a×a×b×b×c

Factors of 27abc3=3×3×3×a×b×c×c×c

Common factors =3×a×b×c

∴ H.C.F =3abc

Step-by-step explanation:

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Answer 2

The factors of the given polynomial are (a/6) and (5a+3bc).

Step-by-step explanation:

The given polynomial can be factorized as follows:

$\frac{5}{6}a^2 +\frac{2}{3}abc -\frac{1}{6}abc = 0$

Taking the LCM first

$\frac{5a^2 + 4abc - abc}{6} = 0$

Subtracting

$\frac{5a^2 + 3abc}{6} = 0$

Taking common terms

$\frac{a}{6} (5a + 3bc) = 0$

So, factors are (a/6) and (5a+3bc).