Question

Factorise of (x-y)^2 - z^2 *​

Answer 1

$\huge\purple{\underline{\underline{\pink{Ans}\red{wer:-}}}}$

$\sf{Factorised \ form \ of \ (x-y)^{2}-z^{2}}$

$\sf{is \ (x-y+z)(x-y-z)}$

$\sf\orange{Given:}$

$\sf{\implies{(x-y)^{2}-z^{2}}}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{\implies{(x-y)^{2}-z^{2}}}$

$\sf{By \ identity}$

$\sf{a^{2}-b^{2}=(a+b)(a-b)}$

$\sf{\implies{(x-y+z)(x-y-z)}}$

$\sf\purple{\tt{\therefore{Factorised \ form \ of \ (x-y)^{2}-z^{2}}}}$

$\sf\purple{\tt{is \ (x-y+z)(x-y-z)}}$

Answer 2

Answer:

using the identity a²-b²=(a+b)(a-b)

given:(x-y)²-z²

solution:(x-y+z)(x-y-z)

the final answer:(x-y+z)(x-y-z)