Question

factorise of x2 -3x -2​

Answer 1

Correct question:

Factorise ${x}^{2}-3x+2$

Answer:

$\large\boxed{\sf{(x-1)(x-2)}}$

Step-by-step explanation:

Given there is an algebraic expression,

${x}^{2} - 3x + 2$

Clearly, it's a quadratic polynomial.

Therefore, it's factor will be in the form of (x±a)(x±b).

Now, we have to factorise this expression.

For this, we have break the middle term as sum of two terms such that, whose produt will be equal to the product of other two terms.

Now, expanding the middle term, we will get,

$= {x}^{2} - 2x - x + 2$

Clearly, we have, $2\times{x}^{2} = (-2x)\times(-x)$.

Now, taking the common terms, we get,

$= x(x - 2) - 1(x - 2) \\ \\ = (x - 2)(x - 1)$

Hence, the factors are (x-2) and (x-1)

Answer 2

Step-by-step explanation:

x² - 3x - 2

= x² - 2x - 1x - 2 ( 2* 1 = 2 , 2 + 1 = 3 )

now we can factorise easily.....

x ( x - 2) - 1 ( x - 2 )

( x - 2 ) ( x - 1 )

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