Question

factorise of x3+2x^2-13x+10​

Answer 1

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Answer:

(x-1) (x-2) (x+5)

Step-by-step explanation:

Let p(x) = x³ +2x² -13x +10

Factors of constant term are ±1, ±2, ±5, ±10.

p(1)= 1³ +2(1)² -13(1) +10

= 1+2 -13+10

= -3 +3

= 0

=> x -1 is a factor of p(x)

_____________

x-1 | x³ +2x² -13x +10 | x² + 3x -10

x³ -x²

____

3x² -13x

3x² -3x

______

-10x +10

-10x +10

_______

0

=> p(x) = (x-1) (x² +3x -10)

= (x-1) (x² -2x +5x -10)

= (x-1) [x(x-2) +5(x-2)]

= (x-1) (x-2) (x+5)