Question

factorise of y square + 2 Y + 10​

Answer 1

Answer:

Step-by-step explanation:

$y^{2}$+2y+10

FORMULA

$y^{2}$= $\frac{-b+/-\sqrt{b^{2-4ac} } }{2a}$

a= coefficient of $y^{2}$

b= coefficient of y

c= constant

Now, substitute in the formula

=$\frac{-2+/-\sqrt{2^{2}-40 } }{2}$

={-2+/-$\sqrt{4-40}$}/2

={-2+/-$\sqrt{36}$}/2

=-$\frac{-2+/-6}{2}$

=$\frac{-2+6}{2} =0$ or $\frac{-2-6}{2} =0$

$\frac{4}{2} =0$ or $\frac{-8}{2}=0$

2 or -4 is  the root of this equaion

Thus y=2or y=-4

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