Question

factorise p^2-14p+24​

Answer 1

${p}^{2} - 14p + 24 = 0 \\ {p}^{2} - (12 + 2)p + 24 = 0 \\ {p}^{2} - 12p - 2p + 24 = 0 \\ p(p - 12) - 2(p - 12) = 0 \\ (p - 12)(p - 2)$

Answer 2

Answer:

p^2-(12+2)p+24=0

p^2-12p-2p+24=0

p(p-12)-2(p-12)=0

(p-12)(p-2)=0

p-12=0 ,p-2=0

p=12 ,p=2