Math, asked by abhinavkrishna2205, 7 months ago

factorise p^2 - 16q^2

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Answered by Anonymous

4

$p { }^{2} - 16q {}^{2} \\ { p} {}^{2} - {4q} {}^{2} \\ {p - 4q} \: \: { p + 4q} \\$

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