Math, asked by jyothsna22, 11 months ago

factorise:p^2-23p+132​

Answers

Answered by saloniii20
21

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Answered by Dhruv4886
5

On factoring p²- 23p + 132​  we will get (p - 11) (p - 12)  

Given:

p²- 23p + 132​

To find:

Factorization of p²- 23p + 132​

Solution:

Given  p²- 23p + 132​  

Split the middle term -23p  as - 11p and - 12p [ ∵ 11 × 12 = 132 ]  

then p²- 23p + 132​  can be written as

⇒ p²- 11p -12p + 132​

Take p common from p² and -11p, take -12p common from -12p and 132​

⇒  p(p - 11) -12 (p - 11)

Take common (p - 11)

⇒  (p - 11) (p - 12)  

On factoring p²- 23p + 132​  we will get (p - 11) (p - 12)  

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