factorise:p^2-23p+132
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On factoring p²- 23p + 132 we will get (p - 11) (p - 12)
Given:
p²- 23p + 132
To find:
Factorization of p²- 23p + 132
Solution:
Given p²- 23p + 132
Split the middle term -23p as - 11p and - 12p [ ∵ 11 × 12 = 132 ]
then p²- 23p + 132 can be written as
⇒ p²- 11p -12p + 132
Take p common from p² and -11p, take -12p common from -12p and 132
⇒ p(p - 11) -12 (p - 11)
Take common (p - 11)
⇒ (p - 11) (p - 12)
On factoring p²- 23p + 132 we will get (p - 11) (p - 12)
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