Question

Factorise p^2 - 3pq + 2q^2

Answer 1

p²-3pq+2q²
p²-2pq-pq+2q²
p(p-2q)-q(p-q)
(p-2q)(p-q)

Answer 2

${p}^{2} - pq - 2pq + 2 {q}^{2} = 0 \\ p(p - q) - 2q(p - q) = 0\\ (p - 2q)(p - q) = 0 \\ p = q \\ p = 2q$