Factorise : p^2 + pq + q^2/4+1+2p+q
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Solution: Given: p2 + pq + q2/4 + 1 + 2p + q We can rewrite the given equation as = p2 + (q/2)2 + 12 + pq + 2p + q = p2 + (q/2)2 + 12 + 2(p)(q/2) + 2(p)(1) + 2(1)(q/2) = (p + q/2 + 1)2 [ ∵ a2 + b2 + c2 + 2ab + 2bc + 2ca = (a + b + c)2 ]
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