Question

factorise p+22p+85
${p }^{2} + 22p + 85$
​

Answer 1

Step-by-step explanation:

please mark me as brainliest

Answer 2

Answer:

Solution for p^2+22p+85=0 equation:

Simplifying

p2 + 22p + 85 = 0

Reorder the terms:

85 + 22p + p2 = 0

Solving

85 + 22p + p2 = 0

Solving for variable 'p'.

Factor a trinomial.

(17 + p)(5 + p) = 0

Subproblem 1

Set the factor '(17 + p)' equal to zero and attempt to solve:

Simplifying

17 + p = 0

Solving

17 + p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-17' to each side of the equation.

17 + -17 + p = 0 + -17

Combine like terms: 17 + -17 = 0

0 + p = 0 + -17

p = 0 + -17

Combine like terms: 0 + -17 = -17

p = -17

Simplifying

p = -17

Subproblem 2

Set the factor '(5 + p)' equal to zero and attempt to solve:

Simplifying

5 + p = 0

Solving

5 + p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-5' to each side of the equation.

5 + -5 + p = 0 + -5

Combine like terms: 5 + -5 = 0

0 + p = 0 + -5

p = 0 + -5

Combine like terms: 0 + -5 = -5

p = -5

Simplifying

p = -5

Solution

p = {-17, -5}