Question

factorise p^2q-pr^2-pq+r^2

Answer 1

Answer:

Step-by-step explanation:

p^2q-pq-pr^2+r^2

p^2q-pq-pr^2+r^2

pq (p-1)-r^2(p-1)

(pq-r^2)(p-1)

Answer 2

Given : The given algebraic expression is, p²q-pr²-pq+r²

To find : The factorisation of the given algebraic expression.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to factorise the given algebraic expression)

Here, we will be using general algebraic method to factorise the given algebraic expression.

So,

= p²q-pr²-pq+r²

= p²q-pq-pr²+r²

= pq(p-1) - r²(p-1)

= (p-1) (pq-r²)

(This cannot be further factorised. That's why, this will be considered as the final result.)

Hence, the answer to the factorisation is (p-1) (pq-r²)