Question

Factorise: p 3 + 13p 2 + 32p + 20

Answer 1

Answer:

thodi der me bhej ta hu mai bhi kar raha hu abhi

Answer 2

Answer:

Mark me as a brainlinest

Step by Step explanation:

By trial and eror method::

step1>> Firstly we have to see the constant term here which is 20.

Step2>> we have to find the factor of constant term

so here, 20- 1,2,4,5,10,20

Step3>> let's take (x+1) is factor of p³+13²+32p+20

step4>> if by taking any of the factor the result given is 0 then the factor of 20 is the equations factor..

let's solve it::

p+1=0

p= -1

Therefore, p(-1)= -1³ + 13(1)² + 32p + 20

= (-1) + 169 + 32(1) + 20

= 169 - 1 + 52

= 168+52=220

so (p-1) is not a factor of p³+13p²+32p+20..

In this way you can solve for (p+5)

p+5=0

p=-5

therefore, p(-5)= (-5)³+ 13(-5)² + 32 (-5) + 20

= -125+13(25)+(-160)+20

= -125+325-160+20

= 325-125-160+20

= 200-160+20

= 40+20=60

(p+5) is also not a factor..

Again by trial and eror method you can try for 4,5,10 and 20.