Question

factorise (p-3)^3+343​

Answer 1

Answer:

(p+4)(p²-13p+79)

Explanation:

(p-3)³+343

= (p-3)³+7³

________________________

We know the algebraic identity:

x³+y³ = (x+y)(x²-xy+y²)

________________________

= (p-3+7)[(p-3)²-(p-3)7+7²]

= (p+4)[p²-2*p*3+3²-7p+21+49]

=(p+4)[p²-6p+9-7p+70]

=(p+4)(p²-13p+79)

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