factorise (p-3)^3+343
Answers
Answered by
2
Answer:
(p+4)(p²-13p+79)
Explanation:
(p-3)³+343
= (p-3)³+7³
________________________
We know the algebraic identity:
x³+y³ = (x+y)(x²-xy+y²)
________________________
= (p-3+7)[(p-3)²-(p-3)7+7²]
= (p+4)[p²-2*p*3+3²-7p+21+49]
=(p+4)[p²-6p+9-7p+70]
=(p+4)(p²-13p+79)
••••
Similar questions