factorise (p+5)²+2(p+5)
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hello users ...
given that:
(p+5)²+2(p+5) = 0
we have to find the value of p = ?
solution:-
here ,
(p+5)²+2(p+5)= 0
=> ( p + 5) [ ( p+5) + 2] = 0 ...taking (p+5) common ...
=> ( p + 5)( p+7) = 0
=> p+5 = 0 and p + 7 = 0
=> p = - 5 and p = -7
=> p = -5,-7 Answer
# hope it helps :)
given that:
(p+5)²+2(p+5) = 0
we have to find the value of p = ?
solution:-
here ,
(p+5)²+2(p+5)= 0
=> ( p + 5) [ ( p+5) + 2] = 0 ...taking (p+5) common ...
=> ( p + 5)( p+7) = 0
=> p+5 = 0 and p + 7 = 0
=> p = - 5 and p = -7
=> p = -5,-7 Answer
# hope it helps :)
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