Question

factorise P Cube QCube + 64​

Answer 1

Step-by-step explanation:

p³q³ + 64

(pq)³ + 4³

[a³+b³ = (a+b)³(a²-ab+b²)]

=(pq+4)³(p²q²-ab+b²)

please mark my answer as brainlist if you are satisfied my friend