Question

factorise (p_q)^2_6(p_q)_16​

Answer 1

Answer:

Hey mate!

Here is your answer > >

(p-q)²-6(p-q)-16

Put (p-q)=A

A^2-6A-16

By mid term splitting method

A^2+8A-2A-16

A (A+8)-2 (A+8)

(A-2)(A+8)

Putting value of A

(p-q-2)(p-q+8)

Hope it helps!

Answer 2

We have,

$\sf{(p - q) {}^{2} - 6(p - q) - 16 = 0}$

Let y = p - q

Here,

y² - 6y -16=0

→y² -8y +2y -16=0

→y(y-8)+2(y-8)=0

→(y-2)(y+8)=0

→y - 2=0 or, y + 8=0

→y=2 or y = -8

→y=2,-8

Implies,

p - q=2 or, p - q= -8

The solutions of the equation are 2 and -8