Question

factorise (p-q)^2-6(p-q)-16​

Answer 1

Answer:

(p-q)²-6(p-q)-16 = (p-q-8)(p-q)

Step-by-step explanation:

(p-q)²-6(p-q)-16

= (p-q)²-8(p-q)+2(p-q)-16

= (p-q)(p-q-8)+2(p-q-8)

= (p-q-8)(p-q)

Therefore,

(p-q)²-6(p-q)-16 = (p-q-8)(p-q)

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Answer 2

(p - q - 8) (p - q + 2)

Step-by-step explanation:

Given,

(p - q)²- 6(p - q) - 16

(p - q)²- 6(p - q) - 16

Splitting the middle expression:

(p - q)² - 8(p - q) +2(p - q) -  16

Taking the common out from the expressions:

(p - q) (p - q - 8) + 2(p - q - 8)

Taking the common out from the expressions:

(p - q - 8) (p - q) + 2)

(p - q - 8) (p - q + 2)

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