factorise (p+q)^3-p-q
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Answered by
29
Hi ,
( p + q )³ - p - q
= ( p + q )³ - ( p + q )
= ( p + q ) [( p + q )² - 1 ]
= ( p + q ) [ ( p + q )² - 1² ]
= ( p + q ) ( p + q + 1 ) ( p + q - 1 )
I hope this helps you.
: )
( p + q )³ - p - q
= ( p + q )³ - ( p + q )
= ( p + q ) [( p + q )² - 1 ]
= ( p + q ) [ ( p + q )² - 1² ]
= ( p + q ) ( p + q + 1 ) ( p + q - 1 )
I hope this helps you.
: )
Answered by
5
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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