Question

factorise (p-q)3+(q-r)3+(r-p)3

Answer 1

(p-q)³ + (q-r)³ + (r-p)³

If a³ + b³ + c³ = 0, we can say that a³ + b³ + c³ = 3abc

a³ + b³ + c³ = p³ - q³ + q³ - r³ + r³ - p³ ( positives and negatives are cut )

∴ a³ + b³ + c³ = 0

 a³ + b³ + c³= 3abc
                    = 3 × ( p - q )( q - r )( r - p )
                    = 3(p-q)(q-r)(r-p)


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Answer 2

hey mate here is your answer