Question

factorise - (p-q)^3+(q-r)^3+(r-p)^3

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Answer 1

First lets see if a + b + c = 0 or not...

p-q+q-r+r-p

Fortunately it equals 0...

therefore

Answer = 3(p-q)(q-r)(r-p)

Answer 2

Answer:

Step-by-step explanation:

(p-q)³+(q-r)³+(r-p)³

if x+y+z=0,

then x³+y³+z³=3xyz

let,

(p-q)=x,  (q-r)=y and (r-p)=z

x+y+z

=(p-q)+(q-r)+(r-p)

=p-q+q-r+r-p

=0

so , now

x³+y³+z³=3xyz

(p-q)³+(q-r)³+(r-p)³=3(p-q)(q-r)(r-p)

HOPE IT HELPS

MARK AS BRAINLIEST