Question

factorise=(p-q)^3 + (q-r)^3 + (r-p)^3​

Answer 1

Answer :

3(p-q)(q-r)(r-p)

Explanation:

__________________

We know that ,

If a+b+c = 0 then

a³+b³+c³ = 3abc

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Here ,

a=p-q , b = q-r , c = r-p

Now,

a+b+c

= p-q+q-r+r-p

= 0

Therefore,

(p-q)³+(q-r)³+(r-p)³

= 3(p-q)(q-r)(r-p)

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