Question

Factorise (p-q) cube +(q-r) cube+(r-p) cube

Answer 1

Answer:

-3 x (p-q)x(r-q)x(r-p)

Step-by-step explanation:

Since the cube is being factored the cube just drops down to a negative three.

Answer 2

Answer:

The answer is 3(p-q) (q-r) (r-p)

This is because

${a}^{3} + {b}^{3} + {c}^{3} = 0 \: when \: a = b = c \: or \: if \: a + b + c = 0$