Factorise (p+q-r)^2-(p-q+r)^2 using identity a^2-b^2
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Answer:(p+q-r)^2-(p-q+r)^2
=>(p+q-r+p-q+r)(p+q-r-p-q+r)
=>2p×1
=2p
Step-by-step explanation:
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