factorise p square - 16p + 25 is equal to zero
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p^2 - 16p + 25 = 0
p^2 - 2*8*p + 25 = 0
p^2 - 2*8*p + 8^2 - 8^2 + 25 = 0
(p - 8)^2 = 64 - 25
(p - 8)^2 = 64 - 25 = 39
p - 8 = +/- sqrt(39)
p - 8 = + sqrt(39), p - 8 = - sqrt(39)
p - 8 - sqrt(39) = 0, p - 8 + sqrt(39) = 0,
(p - 8 - sqrt(39))*(p - 8 + sqrt(39)) = 0 ——> Answer
p^2 - 2*8*p + 25 = 0
p^2 - 2*8*p + 8^2 - 8^2 + 25 = 0
(p - 8)^2 = 64 - 25
(p - 8)^2 = 64 - 25 = 39
p - 8 = +/- sqrt(39)
p - 8 = + sqrt(39), p - 8 = - sqrt(39)
p - 8 - sqrt(39) = 0, p - 8 + sqrt(39) = 0,
(p - 8 - sqrt(39))*(p - 8 + sqrt(39)) = 0 ——> Answer
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Answer:
WRONG QUESTION.
I've tried every possibility that I could think of...
Please check the question again.
In case this is the correct question, value of p by using
Shreedharacharya's Rule (Quadratic Formula) is p =
The given equation cannot be factorised.
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