Question

factorise: p square +6 p+8​

Answer 1

Answer:

$p {}^{2} + 6p + 8$

$p {}^{2} + (4 + 2)p + 8$

$p {}^{2} + 4p + 2p + 8$

$p(p + 4) + 2(p + 4)$

$(p + 2)(p + 4)$

Answer 2

p^2+6p+8=0

p^2+2p+4p+8=0

p(p+2)+4 (p+2)

(p+2)(p+4)=0

p+2=0

p+4=0

p=-2

p=-4